3.1043 \(\int \frac {x^5}{(-2+3 x^2) \sqrt [4]{-1+3 x^2}} \, dx\)

Optimal. Leaf size=63 \[ \frac {2}{189} \left (3 x^2-1\right )^{7/4}+\frac {2}{27} \left (3 x^2-1\right )^{3/4}+\frac {4}{27} \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right )-\frac {4}{27} \tanh ^{-1}\left (\sqrt [4]{3 x^2-1}\right ) \]

[Out]

2/27*(3*x^2-1)^(3/4)+2/189*(3*x^2-1)^(7/4)+4/27*arctan((3*x^2-1)^(1/4))-4/27*arctanh((3*x^2-1)^(1/4))

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Rubi [A]  time = 0.05, antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {446, 88, 63, 298, 203, 206} \[ \frac {2}{189} \left (3 x^2-1\right )^{7/4}+\frac {2}{27} \left (3 x^2-1\right )^{3/4}+\frac {4}{27} \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right )-\frac {4}{27} \tanh ^{-1}\left (\sqrt [4]{3 x^2-1}\right ) \]

Antiderivative was successfully verified.

[In]

Int[x^5/((-2 + 3*x^2)*(-1 + 3*x^2)^(1/4)),x]

[Out]

(2*(-1 + 3*x^2)^(3/4))/27 + (2*(-1 + 3*x^2)^(7/4))/189 + (4*ArcTan[(-1 + 3*x^2)^(1/4)])/27 - (4*ArcTanh[(-1 +
3*x^2)^(1/4)])/27

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 88

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 298

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(a/b),
2]]}, Dist[s/(2*b), Int[1/(r + s*x^2), x], x] - Dist[s/(2*b), Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &
&  !GtQ[a/b, 0]

Rule 446

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] &&
NeQ[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {x^5}{\left (-2+3 x^2\right ) \sqrt [4]{-1+3 x^2}} \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {x^2}{(-2+3 x) \sqrt [4]{-1+3 x}} \, dx,x,x^2\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \left (\frac {1}{3 \sqrt [4]{-1+3 x}}+\frac {4}{9 (-2+3 x) \sqrt [4]{-1+3 x}}+\frac {1}{9} (-1+3 x)^{3/4}\right ) \, dx,x,x^2\right )\\ &=\frac {2}{27} \left (-1+3 x^2\right )^{3/4}+\frac {2}{189} \left (-1+3 x^2\right )^{7/4}+\frac {2}{9} \operatorname {Subst}\left (\int \frac {1}{(-2+3 x) \sqrt [4]{-1+3 x}} \, dx,x,x^2\right )\\ &=\frac {2}{27} \left (-1+3 x^2\right )^{3/4}+\frac {2}{189} \left (-1+3 x^2\right )^{7/4}+\frac {8}{27} \operatorname {Subst}\left (\int \frac {x^2}{-1+x^4} \, dx,x,\sqrt [4]{-1+3 x^2}\right )\\ &=\frac {2}{27} \left (-1+3 x^2\right )^{3/4}+\frac {2}{189} \left (-1+3 x^2\right )^{7/4}-\frac {4}{27} \operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\sqrt [4]{-1+3 x^2}\right )+\frac {4}{27} \operatorname {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\sqrt [4]{-1+3 x^2}\right )\\ &=\frac {2}{27} \left (-1+3 x^2\right )^{3/4}+\frac {2}{189} \left (-1+3 x^2\right )^{7/4}+\frac {4}{27} \tan ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )-\frac {4}{27} \tanh ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 51, normalized size = 0.81 \[ \frac {2}{189} \left (3 \left (3 x^2-1\right )^{3/4} \left (x^2+2\right )+14 \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right )-14 \tanh ^{-1}\left (\sqrt [4]{3 x^2-1}\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[x^5/((-2 + 3*x^2)*(-1 + 3*x^2)^(1/4)),x]

[Out]

(2*(3*(2 + x^2)*(-1 + 3*x^2)^(3/4) + 14*ArcTan[(-1 + 3*x^2)^(1/4)] - 14*ArcTanh[(-1 + 3*x^2)^(1/4)]))/189

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fricas [A]  time = 0.87, size = 57, normalized size = 0.90 \[ \frac {2}{63} \, {\left (3 \, x^{2} - 1\right )}^{\frac {3}{4}} {\left (x^{2} + 2\right )} + \frac {4}{27} \, \arctan \left ({\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}}\right ) - \frac {2}{27} \, \log \left ({\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}} + 1\right ) + \frac {2}{27} \, \log \left ({\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}} - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(3*x^2-2)/(3*x^2-1)^(1/4),x, algorithm="fricas")

[Out]

2/63*(3*x^2 - 1)^(3/4)*(x^2 + 2) + 4/27*arctan((3*x^2 - 1)^(1/4)) - 2/27*log((3*x^2 - 1)^(1/4) + 1) + 2/27*log
((3*x^2 - 1)^(1/4) - 1)

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giac [A]  time = 0.50, size = 64, normalized size = 1.02 \[ \frac {2}{189} \, {\left (3 \, x^{2} - 1\right )}^{\frac {7}{4}} + \frac {2}{27} \, {\left (3 \, x^{2} - 1\right )}^{\frac {3}{4}} + \frac {4}{27} \, \arctan \left ({\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}}\right ) - \frac {2}{27} \, \log \left ({\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}} + 1\right ) + \frac {2}{27} \, \log \left ({\left | {\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}} - 1 \right |}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(3*x^2-2)/(3*x^2-1)^(1/4),x, algorithm="giac")

[Out]

2/189*(3*x^2 - 1)^(7/4) + 2/27*(3*x^2 - 1)^(3/4) + 4/27*arctan((3*x^2 - 1)^(1/4)) - 2/27*log((3*x^2 - 1)^(1/4)
+ 1) + 2/27*log(abs((3*x^2 - 1)^(1/4) - 1))

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maple [C]  time = 0.96, size = 141, normalized size = 2.24 \[ \frac {2 \RootOf \left (\textit {\_Z}^{2}+1\right ) \ln \left (-\frac {3 x^{2}+2 \left (3 x^{2}-1\right )^{\frac {3}{4}} \RootOf \left (\textit {\_Z}^{2}+1\right )-2 \left (3 x^{2}-1\right )^{\frac {1}{4}} \RootOf \left (\textit {\_Z}^{2}+1\right )-2 \sqrt {3 x^{2}-1}}{3 x^{2}-2}\right )}{27}+\frac {2 \ln \left (\frac {-3 x^{2}+2 \left (3 x^{2}-1\right )^{\frac {3}{4}}-2 \sqrt {3 x^{2}-1}+2 \left (3 x^{2}-1\right )^{\frac {1}{4}}}{3 x^{2}-2}\right )}{27}+\frac {2 \left (x^{2}+2\right ) \left (3 x^{2}-1\right )^{\frac {3}{4}}}{63} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(3*x^2-2)/(3*x^2-1)^(1/4),x)

[Out]

2/63*(x^2+2)*(3*x^2-1)^(3/4)+2/27*RootOf(_Z^2+1)*ln(-(2*RootOf(_Z^2+1)*(3*x^2-1)^(3/4)-2*RootOf(_Z^2+1)*(3*x^2
-1)^(1/4)-2*(3*x^2-1)^(1/2)+3*x^2)/(3*x^2-2))+2/27*ln((-3*x^2+2*(3*x^2-1)^(3/4)-2*(3*x^2-1)^(1/2)+2*(3*x^2-1)^
(1/4))/(3*x^2-2))

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maxima [A]  time = 1.93, size = 63, normalized size = 1.00 \[ \frac {2}{189} \, {\left (3 \, x^{2} - 1\right )}^{\frac {7}{4}} + \frac {2}{27} \, {\left (3 \, x^{2} - 1\right )}^{\frac {3}{4}} + \frac {4}{27} \, \arctan \left ({\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}}\right ) - \frac {2}{27} \, \log \left ({\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}} + 1\right ) + \frac {2}{27} \, \log \left ({\left (3 \, x^{2} - 1\right )}^{\frac {1}{4}} - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(3*x^2-2)/(3*x^2-1)^(1/4),x, algorithm="maxima")

[Out]

2/189*(3*x^2 - 1)^(7/4) + 2/27*(3*x^2 - 1)^(3/4) + 4/27*arctan((3*x^2 - 1)^(1/4)) - 2/27*log((3*x^2 - 1)^(1/4)
+ 1) + 2/27*log((3*x^2 - 1)^(1/4) - 1)

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mupad [B]  time = 0.85, size = 51, normalized size = 0.81 \[ \frac {4\,\mathrm {atan}\left ({\left (3\,x^2-1\right )}^{1/4}\right )}{27}+\frac {2\,{\left (3\,x^2-1\right )}^{3/4}}{27}+\frac {2\,{\left (3\,x^2-1\right )}^{7/4}}{189}+\frac {\mathrm {atan}\left ({\left (3\,x^2-1\right )}^{1/4}\,1{}\mathrm {i}\right )\,4{}\mathrm {i}}{27} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/((3*x^2 - 1)^(1/4)*(3*x^2 - 2)),x)

[Out]

(4*atan((3*x^2 - 1)^(1/4)))/27 + (atan((3*x^2 - 1)^(1/4)*1i)*4i)/27 + (2*(3*x^2 - 1)^(3/4))/27 + (2*(3*x^2 - 1
)^(7/4))/189

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sympy [A]  time = 18.98, size = 75, normalized size = 1.19 \[ \frac {2 \left (3 x^{2} - 1\right )^{\frac {7}{4}}}{189} + \frac {2 \left (3 x^{2} - 1\right )^{\frac {3}{4}}}{27} + \frac {2 \log {\left (\sqrt [4]{3 x^{2} - 1} - 1 \right )}}{27} - \frac {2 \log {\left (\sqrt [4]{3 x^{2} - 1} + 1 \right )}}{27} + \frac {4 \operatorname {atan}{\left (\sqrt [4]{3 x^{2} - 1} \right )}}{27} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**5/(3*x**2-2)/(3*x**2-1)**(1/4),x)

[Out]

2*(3*x**2 - 1)**(7/4)/189 + 2*(3*x**2 - 1)**(3/4)/27 + 2*log((3*x**2 - 1)**(1/4) - 1)/27 - 2*log((3*x**2 - 1)*
*(1/4) + 1)/27 + 4*atan((3*x**2 - 1)**(1/4))/27

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